Don't give away the answer. Just say whether you can work it out or not. Four prisoners are offered a chance to have their sentences reduced. To win this reward, one of them has to solve a puzzle. If one of them gets it right, they all go free: if any of them gets it wrong, each of them has their sentence doubled.
Each man is blindfolded and has a hat put on his head. They are all told that there are two black hats and two white hats. The prisoners are lined up. The first - "a" - is on a high box, so, when his blindflold is removed he will be able to see the two in front of him. The next one - "b" - is on a lower box, so he will only be able to see the one in front of him. The third - "c" - is standing on the ground, facing a wall. The fourth - "d" is the other side of the wall and cannot see anyone, even when his blindfold is removed.
When their blindfolds are removed, "a" can see "b" and "c"; "b" can see "c"; but neither "c" nor "d" can see anyone. None of the prisoners can see themselves. They are not allowed to turn around or to speak to each other.
The puzzle they have to solve is for one of them correctly to shout out the colour of hat they are wearing.
Their blindfolds are removed simultaneously. Who guesses their own hat colour correctly, first, "a", "b", "c" or "d"?
Comments
If A didn’t call out, then that tells B that he’s hat is a different colour to C.
So I will not tell anyone I think it's A.
I will just think it quietly to myself
He probably doesn't though.
...*should be...